Calculate the height of a cliff if it takes 2.35s for a rock to hit the ground when it is thrown straight up from the cliff with a initial v

Question

Calculate the height of a cliff if it takes 2.35s for a rock to hit the ground when it is thrown straight up from the cliff with a initial velocity 8m/s.​

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Thu Cúc 3 years 2021-08-27T07:15:36+00:00 1 Answers 10 views 0

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    2021-08-27T07:17:00+00:00

    Answer:

    y₀ = 10.625 m

    Explanation:

    For this exercise we will use the kinematic relations, where the upward direction is positive.

             y = y₀ + v₀ t – ½ g t²

    in the exercise they indicate the initial velocity v₀ = 8 m / s.

    when the rock reaches the ground its height is zero

             0 = y₀ + v₀ t – ½ g t²

            y₀i = -v₀ t + ½ g t²

    let’s calculate

             y₀ = – 8  2.5 + ½  9.8  2.5²

             y₀ = 10.625 m

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