Calculate the electric field acting on the electron in a hydrogen atom due to the proton in the nucleus the radius of the orbit of the elect

Question

Calculate the electric field acting on the electron in a hydrogen atom due to the proton in the nucleus the radius of the orbit of the electron is 5.3×10^-11

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Thu Cúc 6 months 2021-07-14T08:06:07+00:00 1 Answers 33 views 0

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    2021-07-14T08:07:58+00:00

    Answer:

    F=-8.2*10^{-8}N

    Explanation:

    From the question we are told that:

    Radius r=5.3*10^{-11}

    Where

    Proton Charge q_1=1.6*10^{-19}C

    Charge of Electron q_2=-1.6*10^{-19}C

    Generally the equation for Coulomb’s Law is mathematically given by

     F=\frac{9*10^9(q_1)(q_2)}{r^2}

     F=\frac{9*10^9(1.6*10^{-19}C)(-1.6*10^{-19}C)}{5.3*10^{-11}}

     F=-8.2*10^{-8}N

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