Calcium-41 is being used in studies testing the effectiveness of drugs for preventing osteoporosis. The half-life of calcium-41 is 100

Question

Calcium-41 is being used in studies testing the effectiveness of drugs for preventing osteoporosis. The half-life of calcium-41 is 100,000 years. If 20 grams of calcium-41 are present initially, how long would it take until only 2 grams
remains?​

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Thành Đạt 5 months 2021-08-26T01:09:00+00:00 1 Answers 2 views 0

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    0
    2021-08-26T01:10:26+00:00

    Answer:

    332,193 years

    Step-by-step explanation:

    From the question above, we are to calculate the time in an half life question, hence, the formula is given as

    t = In(Nt/No) ÷ -(In2/t½)

    Where

    t = time is takes for an substance to decay or reduce

    Nt = Amount of sample after time = 2g

    No = Initial amount of sample = 20g

    t½ = Half life = 100,000 years

    Hence,

    t = In(2/20) ÷ (In 2/ 100,000)

    t = 332192.80948874 years

    Approximately = 332,193 years

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )