Các bạn giúp mik giải hai bài này vs nhé

`1a,(2x-3)^2+(4x-5)(x-7)`

`=4x^2-12x+9+4x^2-33x+35` 

`=8x^2-45x+44`

`b,(x-2)(x+1)(x+2)-(x-1)^3`

`=x^3+x^2-4x-4-x^3+3x^2-3x+1`

`=4x^2-7x-3`

`c,(2x+5)(5-2x)+(3x-7)(x+2)`

`=-4x^2+25+3x^2-x-14`

`=-x^2-x+11`

`d,(2x+4)^2-(3x-5)^2`

`=4x^2+16x+10-9x^2+30x-25`

`=-5x^2+46x-15`

`2a,(2x-3)(x+1)-2(x-1)^2=3`

`<=>2x^2+2x-3x-3-2x^2+4x-2=3`

`<=>3x-5=3`

`<=>3x=8`

`<=>x=8/3`

Vậy `x=8/3`

`b,(4x+5)(2x-1)-(x+2)^2=(x-3)(x+3)`

`<=>8x^2-4x+10x-5-x^2-4x-4=x^2-9`

`<=>7x^2+2x=x^2`

`<=>6x^2+2x=0`

`<=>2x(3x+1)=0`

`<=>x=0` hoặc `x=-1/3`

Vậy `S={0;-1/3}`

`c,(x-2)^2+(x+3)^2=(x+1)^2+15`

`<=>2x^2+2x+13=x^2+2x+1+15`

`<=>x^2-16+13=0`

`<=>x^2=3`

`<=>x=` `+-`$\sqrt[]{3}$ 

Vậy `x=+-` $\sqrt[]{3}$