Balance the following equations: 1) C2H402+_02->_C02+ _H20 2) V205+ _CaS→_Ca0+ V2S5 3) S8+_O2->_SO2

Question

Balance the following equations:
1) C2H402+_02->_C02+ _H20
2) V205+ _CaS→_Ca0+ V2S5

3) S8+_O2->_SO2

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Nem 4 years 2021-09-05T06:49:09+00:00 1 Answers 18 views 0

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  1. dangkhoa
    0
    2021-09-05T06:51:00+00:00
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    Answer:

    1) 0 C2H4O2 + 0 O2 -> 0 CO2 + 0 H2O (balanced)

    2) V2O5 + CaS -> CaO + V2S5

    just additional info: V2O5 is divanadium pentaoxide

    LHS (Left hand side)

    V: 2

    O: 5

    Ca: 1

    S: 1 x 5 [to balance with the right hand side of the equation]

    RHS (Right hand side)

    V: 2

    O: 1 x 5 [to balance with the left hand side of the equation]

    Ca: 1

    S: 5

    When you balance any elements, you have to balance the whole chemical compound.

    Thus,

    V2O5 + 5 CaS –> 5 CaO + V2S5

    LHS CHECK:

    V: 2

    O: 5

    Ca: 5

    S: 5

    RHS CHECK:

    V: 2

    O: 5

    Ca: 5

    S: 5

    3) S8 + O2 -> SO2

    LHS:

    S: 8

    O: 2

    RHS:

    S: 1 x 8 [to balance with LHS]

    O: 2

    When you balance any elements, you have to balance the whole chemical compound.

    S8 + O2 -> 8 SO2

    When we add 8 to the RHS, it gives us 8S, 16 O.

    In order to balance that into the RHS, I need to multiply the O2 by 8, which will give 8(O2) = 16 O particles.

    Therefore, S8 + 8 O2 –> 8 SO2 is the final answer for (3).

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