bài2:tìm x biết: a)1027-4nhânx=175 B)720:[41nhân(2nhânx-5)]=2mũ3nhân5

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bài2:tìm x biết: a)1027-4nhânx=175 B)720:[41nhân(2nhânx-5)]=2mũ3nhân5

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Adela 6 years 2020-10-25T06:54:04+00:00 2 Answers 99 views 0

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  1. Tryphena
    0
    2020-10-25T06:55:32+00:00
    Reply

    \[\begin{array}{*{20}{l}}
    \begin{array}{l}
    a)1027 – 4x = 175\\
     \Leftrightarrow 4x = 1027 – 175\\
     \Leftrightarrow 4x = 852\\
     \Leftrightarrow x = 213
    \end{array}\\

    {b)720:\left[ {41\left( {2x – 5} \right)} \right] = {2^3}.5}\\
    { \Leftrightarrow 720:\left( {82x – 205} \right) = 40}\\
    { \Leftrightarrow 82x – 205 = 18}\\
    { \Leftrightarrow 82x = 18 + 205}\\
    { \Leftrightarrow 82x = 223}\\
    { \Leftrightarrow x = \dfrac{{223}}{8}}
    \end{array}\]

  2. Verity
    0
    2020-10-25T06:55:34+00:00
    Reply

       a ) 1027- 4  × $x^{}$ =175 

                      4 × $x^{}$   = 1027 – 175

                      4 × $x^{}$   = 852

                             $x^{}$   = 852 ÷ 4

                            $x^{}$    = 213

      B ) 720:  [41 × (2 ×$x^{}$ -5)]= $2^{3}$ x 5

         720 : [ 41 × (2 ×$x^{}$ -5)]= 8 × 5

         720 : [ 41 × (2 ×$x^{}$ -5)]=40

           82 × $x^{}$ = 720 : 40

         82 × $x^{}$ – 205   = 18

             82 ×  $x^{}$   = 18 + 205

            82 ×  $x^{}$    = 223

                      $x^{}$    = 223 ÷ 82

                      $x^{}$    = $\frac{223}{82}$ 

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )