Bài 37 thôi nha 20 điểm và vote 5 sao

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Bài 37 thôi nha 20 điểm và vote 5
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bai-37-thoi-nha-20-diem-va-vote-5-sao

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Khải Quang 6 years 2020-11-21T11:50:27+00:00 1 Answers 64 views 0

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  1. kiet
    0
    2020-11-21T11:51:36+00:00
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    Đáp án:

     

    Giải thích các bước giải:

    a)   \(\dfrac{4^{2}.4^{3}}{2^{10}} = \dfrac{4^{2+3}}{2^{2.5}}\)\(= \dfrac{4^{5}}{(2^{2})^{5}}=\dfrac{4^{5}}{4^{5}}= 1\)

    b) \(\dfrac{(0,6)^{5}}{(0,2)^{6}} = \dfrac{(0,2.3)^{5}}{(0,2)^{5+1}} = \dfrac{(0,2)^{5}.3^{5}}{(0,2)^{5}.0,2} \)

    \(= \dfrac{3^{5}}{0,2} = \dfrac{243}{0,2}= 1215\)

    c) \(\dfrac{{{2^7}{{.9}^3}}}{{{6^5}{{.8}^2}}} = \dfrac{{{2^7}.{{\left( {{3^2}} \right)}^3}}}{{{{\left( {2.3} \right)}^5}.{{\left( {{2^3}} \right)}^2}}}\)\(= \dfrac{{{2^7}{{.3}^{2.3}}}}{{{2^5}{{.3}^5}{{.2}^{3.2}}}} = \dfrac{{{2^7}{{.3}^6}}}{{{2^5}{{.3}^5}{{.2}^6}}} \)

    \(= \dfrac{{{2^7}{{.3}^6}}}{{{2^{11}}{{.3}^5}}} = \dfrac{3}{{{2^4}}} = \dfrac{3}{{16}}\)

    \(\eqalign{
    & d)\,\,{{{6^3} + {{3.6}^2} + {3^3}} \over { – 13}}\cr& = {{{{\left( {2.3} \right)}^3} + 3.{{\left( {2.3} \right)}^2} + {3^3}} \over { – 13}} \cr
    & = {{{2^3}{{.3}^3} + {3^3}{{.2}^2} + {3^3}} \over { – 13}} \cr&= {{{3^3}.({2^3} + {2^2} + 1)} \over { – 13}} \cr
    & = {{{3^3}.13} \over { – 13}} = {{{3^3}} \over { – 1}} = – 27 \cr} \)

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