b(1)= -12 b(n)=b(n−1)⋅4 Find the 3rd term of the sequence. Show me the solutions and calculations.​

Question

b(1)= -12

b(n)=b(n−1)⋅4

Find the 3rd term of the sequence. Show me the solutions and calculations.​

in progress 0
Thiên Thanh 5 years 2021-07-22T16:45:08+00:00 1 Answers 22 views 0

Answers ( )

  1. Sapo1
    0
    2021-07-22T16:46:30+00:00
    Reply

    Given:

    b(1)=-12

    b(n)=b(n-1)\cdot 4

    To find:

    The third term of the sequence.

    Solution:

    We have,

    b(n)=b(n-1)\cdot 4

    For n=2, we get

    b(2)=b(2-1)\cdot 4

    b(2)=b(1)\cdot 4

    b(2)=-12\cdot 4              [\because b(1)=-12]

    b(2)=-48

    For n=3, we get

    b(3)=b(3-1)\cdot 4

    b(3)=b(2)\cdot 4

    b(3)=-48\cdot 4              [\because b(2)=-48]

    b(3)=-192

    Therefore, the 3rd term of the sequence is -192.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )