Assume that charge −q−q-q is placed on the top plate, and +q+q+q is placed on the bottom plate. What is the magnitude of the electric field

Question

Assume that charge −q−q-q is placed on the top plate, and +q+q+q is placed on the bottom plate. What is the magnitude of the electric field EEE between the plates?

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Delwyn 4 years 2021-09-02T21:32:19+00:00 1 Answers 26 views 0

Answers ( )

  1. kiet
    0
    2021-09-02T21:34:03+00:00
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    Answer:

    Magnitude of electric field = E = q/Aε0

    Explanation:

    Consider plates are placed at a distance of d. As given in the question the charge stored on the plates have magnitude q and given by:

                                              q = CV

    And  

                                              V = q/C    ……. (i)

    The capacitance is given by the following equation:  

                                             C = Aε0/d ……. (ii)

    Put equation (ii) in (i)
    ,

                                              V = qd/ Aε0 …..(iii)    

    The electric field is defined as:  

                                                E = V/d   …… (iv)

    Put equation (iii) in (iv),

                                                E = qd/ Aε0d

                                                E = q/Aε0

    Hence, the magnitude of electric field will be q/Aε0 .

                                             

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