(ASAP) Billie & Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen years older th

Question

(ASAP) Billie & Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen years older than Billie. What are the ages of Billie & Tony?

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Mộc Miên 4 years 2021-08-04T23:03:23+00:00 2 Answers 16 views 0

Answers ( )

  1. thugiang
    0
    2021-08-04T23:05:12+00:00
    Reply

    Answer:

    Billie’s age = x = 17 years

    Tony’s age = y = 31 years

    Step-by-step explanation:

    Let

    Billie’s age = x

    Tony’s age = y

    Twice Billie’s age decreased by 3 is Tony’s age.

    y = 2x – 3….. Equation 1

    Tony is fourteen years older than Billie.

    x = y – 14

    We substitute y – 14 for x in Equation 1

    y = 2x – 3….. Equation 1

    y = 2(y – 14) – 3

    y = 2y – 28 – 3

    y – 2y = -28 – 3

    -y = -31

    y = 31 years

    Solving for x

    x = y – 14

    x = 31 – 14

    x = 17 years.

    Therefore:

    Billie’s age = x = 17 years

    Tony’s age = y = 31 years

  2. King
    0
    2021-08-04T23:05:18+00:00
    Reply

    Answer:

    I agree with this person 🙂

    Step-by-step explanation:

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