(ASAP) Billie & Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen years older than Billie. What are the ages of Billie & Tony?
(ASAP) Billie & Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen years older than Billie. What are the ages of Billie & Tony?
Answer:
Billie’s age = x = 17 years
Tony’s age = y = 31 years
Step-by-step explanation:
Let
Billie’s age = x
Tony’s age = y
Twice Billie’s age decreased by 3 is Tony’s age.
y = 2x – 3….. Equation 1
Tony is fourteen years older than Billie.
x = y – 14
We substitute y – 14 for x in Equation 1
y = 2x – 3….. Equation 1
y = 2(y – 14) – 3
y = 2y – 28 – 3
y – 2y = -28 – 3
-y = -31
y = 31 years
Solving for x
x = y – 14
x = 31 – 14
x = 17 years.
Therefore:
Billie’s age = x = 17 years
Tony’s age = y = 31 years
Answer:
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Step-by-step explanation: