Question (ASAP) Billie & Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen years older than Billie. What are the ages of Billie & Tony?

Answer: Billie’s age = x = 17 years Tony’s age = y = 31 years Step-by-step explanation: Let Billie’s age = x Tony’s age = y Twice Billie’s age decreased by 3 is Tony’s age. y = 2x – 3….. Equation 1 Tony is fourteen years older than Billie. x = y – 14 We substitute y – 14 for x in Equation 1 y = 2x – 3….. Equation 1 y = 2(y – 14) – 3 y = 2y – 28 – 3 y – 2y = -28 – 3 -y = -31 y = 31 years Solving for x x = y – 14 x = 31 – 14 x = 17 years. Therefore: Billie’s age = x = 17 years Tony’s age = y = 31 years Log in to Reply

Answer:

Billie’s age = x = 17 years

Tony’s age = y = 31 years

Step-by-step explanation:

Let

Billie’s age = x

Tony’s age = y

Twice Billie’s age decreased by 3 is Tony’s age.

y = 2x – 3….. Equation 1

Tony is fourteen years older than Billie.

x = y – 14

We substitute y – 14 for x in Equation 1

y = 2x – 3….. Equation 1

y = 2(y – 14) – 3

y = 2y – 28 – 3

y – 2y = -28 – 3

-y = -31

y = 31 years

Solving for x

x = y – 14

x = 31 – 14

x = 17 years.

Therefore:

Billie’s age = x = 17 years

Tony’s age = y = 31 years

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Step-by-step explanation: