## As new-forming stars grow by gravitationally attracting more material, they become brighter. If a star becomes too bright, the radiation pre

Question

As new-forming stars grow by gravitationally attracting more material, they become brighter. If a star becomes too bright, the radiation pressure from the star prevents gravity from pulling in more material. What power output PP would a star with a mass 35.135.1 times that of our Sun need to have in order to be unable to pull in a 3.96 μg3.96 μg dust particle of radius rp=0.935 mm,rp=0.935 mm, assuming the particle absorbs all the light incident on its πr2pπrp2 cross‑section? The mass ????⊙M⊙ of the Sun is 1.99×1030 kg,1.99×1030 kg, and the gravitational constant GG equals 6.67×10−11 m3/(kg·s2).

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3 years 2021-07-23T19:36:57+00:00 2 Answers 61 views 0

The power output of the star is 2.215×10²⁸W

Explanation:

Given data:

ms = mass of the star = 35.135 times msun

rp = radius = 0.935 mm = 9.35×10⁻⁴m

p = 3.46 μg = 3.46×10⁻⁹g

msun = mass of the Sun = 1.99×10³⁰kg

G = gravitational constant = 6.67×10⁻¹¹m³/kg s²

c = speed of light = 3×10⁸m/s

Question: What power ouput would a star, P = ?

First, calculate the mass of the star:

The power output of the star: