Anthony and Sissy are participating in the “Roll-a-Rama” rollerskating dance championship. While 75.0-kg Anthony roller skates backwards at

Question

Anthony and Sissy are participating in the “Roll-a-Rama” rollerskating dance championship. While 75.0-kg Anthony roller skates backwards at 3.0 m/s,60.0-kg Sissy jumps into his arms with a velocity of 5.0 m/s in the same direction. How fast does the pair roll backwards together?

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Thiên Ân 3 years 2021-08-19T08:37:52+00:00 1 Answers 78 views 0

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    2021-08-19T08:39:49+00:00

    Answer:

    V = 3.89m/s

    Explanation:

    Given Ma = 75.0kg, Va = 3.0m/s, Ms = 60.0kg and Vs = 5.0m/s

    Since the pair roll backwards after Sissy jumps into Anthony’s arms,

    let the common velocity of the pair be V

    From the principle of conservation of momentum,

    Total momentum before collision is equal to the total momentum after collision

    MaVa + MsVs = (Ma + Ms) × V

    V = (MaV + MsVs)/(Ma + Ms)

    V = (75×3 + 60×5)/ (75 + 60) = 3.89m/s

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