ANSWER ASAP GIVING BRAILIEST AND STUFF! Please answer the following essay question: Suppose each dimension of a cube is increase

Question

ANSWER ASAP GIVING BRAILIEST AND STUFF!
Please answer the following essay question:
Suppose each dimension of a cube is increased. What happens to the surface area when each dimension is doubled, tripled or, quadrupled?

in progress 0
Ngọc Khuê 5 years 2021-07-18T15:35:39+00:00 1 Answers 17 views 0

Answers ( )

  1. minhkhoi
    0
    2021-07-18T15:36:41+00:00
    Reply

    Answer:

    24s^2, 54s^2, 96s^2

    Step-by-step explanation:

    Let s represent the initial side length of the cube.  Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).

    a) Now suppose we double the side length.  The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),

    b) tripled:  A = 6(3s)^2 = 54x^2

    c) quadrupled?  A = 6(4s)^2 = 96s^2

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )