Share
ANSWER ASAP GIVING BRAILIEST AND STUFF! Please answer the following essay question: Suppose each dimension of a cube is increase
Question
ANSWER ASAP GIVING BRAILIEST AND STUFF!
Please answer the following essay question:
Suppose each dimension of a cube is increased. What happens to the surface area when each dimension is doubled, tripled or, quadrupled?
in progress
0
Mathematics
5 years
2021-07-18T15:35:39+00:00
2021-07-18T15:35:39+00:00 1 Answers
14 views
0
Answers ( )
Answer:
24s^2, 54s^2, 96s^2
Step-by-step explanation:
Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).
a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),
b) tripled: A = 6(3s)^2 = 54x^2
c) quadrupled? A = 6(4s)^2 = 96s^2