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## Anand gets into an elevator and travels 50 m straight up in a time of 5 s. He then travels in the opposite direction, straight down, for 70

Question

Anand gets into an elevator and travels 50 m straight up in a time of 5 s. He then travels in the opposite direction, straight down, for 70 m in a time of 6 s. What is his average speed and velocity, respectively, over the 11 s period?

A. 10.9 m/s, 1.82 m/s

B. 10.9 m/s, −1.82 m/s

C. 21.8 m/s, 10.9 m/s

D. −10.9 m/s, 5.2 m/s

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Physics
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2021-09-05T16:44:08+00:00
2021-09-05T16:44:08+00:00 1 Answers
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## Answers ( )

Answer:10.9 m/s, −1.82 m/s

Explanation:We have,

Anand gets into an elevator and travels 50 m straight up in a time of 5 s. He then travels in the opposite direction, straight down, for 70 m in a time of 6 s.

Total time of journey is 11 seconds.

Total distance is 50 m + 70 m = 120 m

Total displacement is 50 m – 70 m = -20 m

Average speed,

Average velocity,

So, the correct option is (b) 10.9 m/s, −1.82 m/s.