Anand gets into an elevator and travels 50 m straight up in a time of 5 s. He then travels in the opposite direction, straight down, for 70

Question

Anand gets into an elevator and travels 50 m straight up in a time of 5 s. He then travels in the opposite direction, straight down, for 70 m in a time of 6 s. What is his average speed and velocity, respectively, over the 11 s period?

A. 10.9 m/s, 1.82 m/s
B. 10.9 m/s, −1.82 m/s
C. 21.8 m/s, 10.9 m/s
D. −10.9 m/s, 5.2 m/s

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Thu Hương 3 years 2021-09-05T16:44:08+00:00 1 Answers 23 views 0

Answers ( )

  1. taiduc
    1
    2021-09-05T16:45:40+00:00
    Reply

    Answer:

    10.9 m/s, −1.82 m/s

    Explanation:

    We have,

    Anand gets into an elevator and travels 50 m straight up in a time of 5 s. He then travels in the opposite direction, straight down, for 70 m in a time of 6 s.

    Total time of journey is 11 seconds.

    Total distance is 50 m + 70 m = 120 m

    Total displacement is 50 m – 70 m = -20 m

    Average speed, s=\dfrac{120\ m}{11\ s}=10.9\ m/s

    Average velocity, v=\dfrac{-20\ m}{11\ s}=-1.82 \ m/s

    So, the correct option is (b) 10.9 m/s, −1.82 m/s.

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