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An orange of mass 3kg falls from a height 50m. When its height is H, its speed is 4m/s? Write an expression that describes the c
Question
An orange of mass 3kg falls from a height 50m. When its height is H, its speed is
4m/s?
Write an expression that describes the conservation of energy with the given
numbers and H. You don’t have to solve for H.
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Physics
3 years
2021-08-25T05:53:24+00:00
2021-08-25T05:53:24+00:00 1 Answers
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Answers ( )
Answer:
(10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s)²
Explanation:
Initially, the orange has only gravitational potential energy.
As the orange falls, it has a combination of potential energy and kinetic energy.
Energy is conserved, so initial energy = final energy:
PE₀ = PE + KE
mgH₀ = mgH + ½ mv²
gH₀ = gH + ½ v²
Plugging in values:
(10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s)²