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An object was thrown from rest upward with an initial velocity of 10m/s with time frame of 6s find the distance of the object from it’s rest
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Answers ( )
Answer: Approx. 120 m below the throw point.
Explanation:
Let throw point be origin and UP the positive direction
s = s₀ + v₀t + ½at²
s = 0 + 10(6) + ½(-9.8)6²
s = -116.4 m