An object was thrown from rest upward with an initial velocity of 10m/s with time frame of 6s find the distance of the object from it’s rest

Question

An object was thrown from rest upward with an initial velocity of 10m/s with time frame of 6s find the distance of the object from it’s resting point​

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Ladonna 5 years 2021-09-02T20:58:41+00:00 1 Answers 12 views 0

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    2021-09-02T21:00:33+00:00

    Answer: Approx. 120 m below the throw point.

    Explanation:

    Let throw point be origin and UP the positive direction

    s = s₀ + v₀t + ½at²

    s = 0 + 10(6) + ½(-9.8)6²

    s = -116.4 m

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