An initially stationary 1.3 kg object accelerates horizontally and uniformly to a speed of 9.4 m/s in 3.0 s. (a) In that 3.0 s interval, how

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An initially stationary 1.3 kg object accelerates horizontally and uniformly to a speed of 9.4 m/s in 3.0 s. (a) In that 3.0 s interval, how much work is done on the object by the force accelerating it

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Diễm Thu 3 years 2021-08-29T05:19:07+00:00 1 Answers 0 views 0

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  1. Farah
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    2021-08-29T05:20:12+00:00
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    Answer: 57.434 Nm

    Explanation: mass of object = 1.3kg, initial speed = 0m/s ( since it was at rest), final speed = 9.4 m/s.

    Using the work energy theorem,

    The work done on the object equals it kinetic energy.

    Work done = mv²/2

    Work done = 1.3 ×( 9.4 – 0)²/2

    Work done = 1.3 × 9.4² / 2

    Work done = 114.868 / 2 = 57.434 Nm

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