An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in contact with

Question

An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in contact with the faux fawn for 0.815 s, after which the car is measured to be traveling at 71.0 km/h. What is the magnitude of the acceleration of the car before the collision

in progress 0
RobertKer 3 years 2021-07-25T23:46:45+00:00 1 Answers 124 views 0

Answers ( )

  1. Ladonna
    0
    2021-07-25T23:47:58+00:00
    Reply

    Answer:

    The value is   a = 4.0 \ m/s^2

    Explanation:

    From the question we are told that  

      The velocity  is  a = 120 \ km/h = [tex]\frac{120 * 1000}{3600} = 33.3 \ m/s[/tex]

      The time taken is t = 8.28 \ s

        The  time taken for contact is  t_c = 0.815 \ s

         The  velocity of the of the car after contact is v_c = 71.0 \ km/h = [tex]\frac{71 *1000}{3600} = 19.7 2 \ m/s[/tex]

    From the equation of kinematics we have that  

           v = u + at

    Here   u =  0 \ m/s  since the car is initially motionless

    =>     33.3 = 0 + a * 8.28

    =>     a = 4.0 \ m/s^2

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )