An ideal gas in a sealed container has an initial volume of 2.35 L. At constant pressure, it is cooled to 23.00 ∘ C , where its f

Question

An ideal gas in a sealed container has an initial volume of 2.35 L. At constant pressure, it is cooled to 23.00 ∘ C , where its final volume is 1.75 L. What was the initial temperature?

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Neala 3 years 2021-08-27T07:58:06+00:00 1 Answers 5 views 0

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    2021-08-27T08:00:03+00:00

    Answer:

    397.5K

    Explanation:

    Given parameters:

    Initial volume = 2.35L

    Final temperature = 23°C

    Final volume = 1.75L

    Unknown:

    Initial temperature = ?

    Solution:

    The Charles’s law states that “the volume of a fixed mass(mole) of a gas varies directly as its absolute temperature if the pressure is constant”.

    Mathematically;

               \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

    where V₁ is the initial volume

               T₁ is the initial temperature

               V₂ is the final volume

               T₂ is the final temperature

    we need to convert  °C to Kelvin;

             23°C; 273 + 23 = 296K

             

            \frac{2.35}{T_{1} }  = \frac{1.75}{296}

              T₁  = 397.5K

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