An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree slope. The ice cube is pressed against a spring at the botto

Question

An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 0.100 m . The spring constant is 25.0 N/m . When the ice cube is released, how far will it travel up the slope before reversing direction?

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Calantha 3 years 2021-08-12T11:51:21+00:00 1 Answers 98 views 0

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    2021-08-12T11:52:33+00:00

    Answer:

    d = 0.604 m

    Explanation:  set 0 GPE at max spring compression, then

    total E = U =  1/2kx^2 = 1/2 25N/m (0.1m)^2  = 0.125 J

    max height,

    GPE = 0.125 J = mgh = 0.05kg 9.8m/s^2 h

    h = 0.255 m

    Along slope,  d = 0.255m / sin25°

    d = 0.604 m

    It’s possible they want the distance from the end of the spring — that’s 0.504 m

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