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An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree slope. The ice cube is pressed against a spring at the botto
Question
An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 0.100 m . The spring constant is 25.0 N/m . When the ice cube is released, how far will it travel up the slope before reversing direction?
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Physics
3 years
2021-08-12T11:51:21+00:00
2021-08-12T11:51:21+00:00 1 Answers
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Answer:
d = 0.604 m
Explanation: set 0 GPE at max spring compression, then
total E = U = 1/2kx^2 = 1/2 25N/m (0.1m)^2 = 0.125 J
max height,
GPE = 0.125 J = mgh = 0.05kg 9.8m/s^2 h
h = 0.255 m
Along slope, d = 0.255m / sin25°
d = 0.604 m
It’s possible they want the distance from the end of the spring — that’s 0.504 m