An ice cube (n = 1.31) has a layer of water (n = 1.33) on it. What is the critical angle for a ray in water trying to enter the ice?

Question

An ice cube (n = 1.31) has a layer of water (n = 1.33) on it. What is the critical angle for a ray in water trying to enter the ice?

(Unit=deg)

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Ngọc Diệp 5 years 2021-08-01T04:36:51+00:00 1 Answers 66 views 0

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  1. dangkhoa
    0
    2021-08-01T04:38:33+00:00
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    Answer:

    Explanation:

    Given that,

    The Refractive index of glass is

    n(ice) = 1.31

    The refractive index of water is

    n(water) = 1.33

    What is the critical angle?

    From water to ice

    Critical angle is given as.

    Using Snell’s Rule.

    Sin( θc ) = n1 / n2

    for total internal reflection the incident ray is always in the denser medium! So, water is the more denser than ice.

    Then, .

    Sin( θc ) = n(ice) / n(water)

    Sin( θc ) = 1.31 / 1.33

    Sin( θc ) = 0.98496

    θc = arcSin(0.98496)

    θc = 80.05°

    The critical angle is 80.05°

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