An ice cream truck is moving along at 20m/s (it’s initial velocity.) It then speed up (accelerates) for 5 seconds at 8m/s^2. What distance w

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An ice cream truck is moving along at 20m/s (it’s initial velocity.) It then speed up (accelerates) for 5 seconds at 8m/s^2. What distance would the truck travel in this time interval

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Thu Hương 4 years 2021-08-10T03:26:48+00:00 1 Answers 177 views 0

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  1. vankhanh
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    2021-08-10T03:28:24+00:00
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    Answer:

    The distance traveled by the truck is 200 m.

    Explanation:

    The expression for the equation of motion is as follows;

    S=ut+\frac{1}{2}at^{2}    

    Here, u is the initial speed, t is the time, a is the acceleration and S is the distance.

    According to the given problem, an ice cream truck is moving along at 20m/s (it’s initial velocity.) It then speed up (accelerates) for 5 seconds at 8 meter per second square.

    Calculate the distance.

    Put u= 20 meter per second, t= 5 s and a= 8 meter per second square in the above expression.

    S=(20)(5)+\frac{1}{2}(8)(5)^{2}

    S= 100+ 100

    S = 200 m

    Therefore, the distance traveled by the truck is 200 m.

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