An engine flywheel initially rotates counterclockwise at 6.77 rotations/s. Then, during 23.9 s, its rotation rate changes to 3.51 rota

Question

An engine flywheel initially rotates counterclockwise at 6.77 rotations/s. Then, during 23.9 s, its rotation rate changes to 3.51 rotations/s clockwise. Find the flywheel’s average angular acceleration (including its sign) in radians per second squared. Define counterclockwise rotation as positive.

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Dulcie 3 years 2021-08-26T05:01:59+00:00 1 Answers 7 views 0

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    2021-08-26T05:03:44+00:00

    Answer:

    -2.70 rad/s²

    Explanation:

    Given that

    ω1 = initial angular velocity of the flywheel, which is 6.77 rev/s

    If we convert it to rad/s, we have

    (6.77 x 2π) rad/s = 13.54π rad/s

    ω2 = final angular velocity of the flywheel = -3.51 rev/s,

    On converting to rad/s also, we have

    (-3.51 x 2π) rad/s = 7.02π rad/s

    α = average angular acceleration of the flywheel = ?

    Δt = elapsed time = 23.9 s

    Now, using the formula, α = (ω2 – ω1)/Δt. On substituting, we have

    α = (-7.02π rad/s – 13.54π rad/s)/23.9 s

    α = -20.56π rad/s / 23.9 s

    α = -64.59 rad/s / 23.9 s

    α = -2.70 rad/s²

    Therefore, the average angular acceleration of the flywheel is -2.70 rad/s²

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