An engine flywheel initially rotates counterclockwise at 5.03 rotations/s. Then, during 23.5 s, its rotation rate changes to 2.63 rotations/

Question

An engine flywheel initially rotates counterclockwise at 5.03 rotations/s. Then, during 23.5 s, its rotation rate changes to 2.63 rotations/s clockwise. Find the flywheel’s average angular acceleration (including its sign) in radians per second squared. Define counterclockwise rotation as positive.

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Diễm Kiều 5 years 2021-08-01T03:43:39+00:00 1 Answers 34 views 1

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  1. minhkhue
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    2021-08-01T03:44:55+00:00
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    Answer:

    the flywheel’s average angular acceleration is -2.05 rad/s²

    Explanation:

    Note: counterclockwise is positive

             clockwise is negative

    Given;

    initial angular velocity, \omega _i = 5.03 rev/s = 5.03\frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 31.61 \ rad/s

    final angular velocity, \omega_f= -2.63 rev/s = -2.63 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = -16.53 \ rad/s

    duration of the flywheel rotation, Δt = 23.5 s

    The average acceleration of the flywheel is calculated as;

    a_r = \frac{\Delta \omega}{\Delta t} = \frac{\omega_f - \omega _i}{t_2-t_1} = \frac{-16.53 \ - \ 31.61}{23.5} = -2.05 \ rad/s^2

    Therefore, the flywheel’s average angular acceleration is -2.05 rad/s²

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