## An electron has a kinetic energy of 10.1 eV. The electron is incident upon a rectangular barrier of height 18.2 eV and width 1.00 nm. If the

Question

An electron has a kinetic energy of 10.1 eV. The electron is incident upon a rectangular barrier of height 18.2 eV and width 1.00 nm. If the electron absorbed all the energy of a photon of green light (with wavelength 546 nm) at the instant it reached the barrier, by what factor would the electron’s probability of tunneling through the barrier increase

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3 years 2021-08-24T02:19:25+00:00 1 Answers 3 views 0

factor that the electron’s probability of tunneling through the barrier increase 2.02029

Explanation:

given data

kinetic energy = 10.1 eV

height = 18.2 eV

width = 1.00 nm

wavelength = 546 nm

solution

we know that probability of tunneling is express as

probability of tunneling =   ……………..1

here C is =

here h is Planck’s constant

c =

c = 2319130863.06

and proton have hf = = 2.27 ev

so electron K.E = 10.1 + 2.27

KE = 12.37 eV

so decay coefficient inside barrier is

c’ =

c’ =

c’ = 1967510340

so

the factor of incerease in transmisson probability is

probability =

probability =

factor probability = 2.02029