an asteroid whose mass is 2.0 x 10^-4 times the mass of earth revolves in a circular orbit around the sun at a distance that is twice the ea

Question

an asteroid whose mass is 2.0 x 10^-4 times the mass of earth revolves in a circular orbit around the sun at a distance that is twice the earth’s distance from the sun calculate the period of revolution of the asteroid in years

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RobertKer 4 years 2021-08-18T22:07:24+00:00 1 Answers 13 views 0

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  1. Delwyn
    0
    2021-08-18T22:09:01+00:00
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    Answer:

    0.0002

    Explanation:

    First you have to solve exponents first, so you solve 10 to the power of negative 4 which is 0.0001 and now you have 2.0×0.0001 and that equals 0.0002

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