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An apparatus like the one Cavendish used to find G has large lead balls that are 5.2 kg in mass and small ones that are 0.046 kg. The center
Question
An apparatus like the one Cavendish used to find G has large lead balls that are 5.2 kg in mass and small ones that are 0.046 kg. The center of a large ball is separated by 0.057 m from the center of a small ball. The Cavendish apparatus for measuring G. As the small spheres of mass m are attracted to the large spheres of mass M, the rod between the two small spheres rotates through a small angle. Find the magnitude of the gravitational force between the masses if the value of the universal gravitational constant is 6.67259 × 10−11 Nm2/kg2. Answer in units of N.
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Physics
3 years
2021-08-26T08:01:23+00:00
2021-08-26T08:01:23+00:00 1 Answers
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Answers ( )
Answer:
The magnitude of gravitational force between two masses is
.
Explanation:
Given that,
Mass of first lead ball,![Rendered by QuickLaTeX.com m_1=5.2\ kg](https://documen.tv/wp-content/ql-cache/quicklatex.com-abf5f158edc5365b32a71f84bdd71d3b_l3.png)
Mass of the other lead ball,![Rendered by QuickLaTeX.com m_2=0.046\ kg](https://documen.tv/wp-content/ql-cache/quicklatex.com-23598805d185864768b3a3b9c01264d8_l3.png)
The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m
We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :
So, the magnitude of gravitational force between two masses is
. Hence, this is the required solution.