An aluminum wire having a cross-sectional area equal to 3.90 10-6 m2 carries a current of 6.00 A. The density of aluminum is 2.70 g/cm3. Ass

Question

An aluminum wire having a cross-sectional area equal to 3.90 10-6 m2 carries a current of 6.00 A. The density of aluminum is 2.70 g/cm3. Assume each aluminum atom supplies one conduction electron per atom. Find the drift speed of the electrons in the wire.

in progress 0
Amity 5 years 2021-08-31T10:02:31+00:00 1 Answers 16 views 0

Answers ( )

  1. Nick
    0
    2021-08-31T10:04:13+00:00
    Reply

    Answer:

    Vd = 1.597 ×10⁻⁴ m/s

    Explanation:

    Given: A = 3.90×10⁻⁶ m², I = 6.00 A, ρ = 2.70 g/cm³

    To find:

    Drift Velocity Vd=?

    Solution:

    the formula is Vd = I/nqA         (n is the number of charge per unit volume)

    n = No. of electron in a mole ( Avogadro’s No.) / Volume

    Volume = Molar mass / density   ( molar mass of Al =27 g)

    V = 27 g / 2.70 g/cm³ = 10 cm³ = 1 × 10 ⁻⁵ m³

    n= (6.02 × 10 ²³) / (1 × 10 ⁻⁵ m³)

    n= 6.02 × 10 ²⁸

    Now

    Vd = (6A) / (  6.02 × 10 ²⁸ ×  1.6 × 10⁻¹⁹ C ×  3.9×10⁻⁶ m²)

    Vd = 1.597 ×10⁻⁴ m/s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )