An airplane takes off a runway at a constant speed of 49m/s at constant angle 30 to the horizontal

Question

An airplane takes off a runway at a constant speed of 49m/s at constant angle 30 to the horizontal

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Doris 5 years 2021-09-01T00:10:38+00:00 1 Answers 14 views 0

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  1. RuslanHeatt
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    2021-09-01T00:12:18+00:00
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    Complete Question

    An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters )  is the airplane above the ground 13 seconds after takeoff?

    Answer:

    The height  is H = 318.5 \ m

    Explanation:

    From the question we are told that

       The speed at which the plane takes off is  u = 49 \ m/s

          The angle at which it takes off is  \theta = 30 ^o

            The time taken is t = 13 s

    The vertical distance traveled is  mathematically represented as

              H = u sin \theta t

    Substituting values  

             H = (49) * sin (30) *13

            H = 318.5 \ m

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