An airplane lands on the runway at a velocity of 22.7m/s. The plane accelerates at a rate of -3.3m/s2 until it comes to rest. How much time

Question

An airplane lands on the runway at a velocity of 22.7m/s. The plane accelerates at a rate of -3.3m/s2 until it comes to rest. How much time does it take the plane to stop? (round to the nearest tenth).

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Thu Thủy 3 years 2021-07-27T12:47:19+00:00 1 Answers 5 views 0

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    2021-07-27T12:48:20+00:00

    Answer:

    time = 6.9 s

    Explanation:

    velocity of the plane v = 22.7 m/s

    acceleration of the train a = -3.3 m/s^2

    it finally comes to res, final velocity u = 0 m/s

    time t = ?

    using the equation

    v = u + at

    substituting, we have

    0 = 22.7  + (-3.3)t

    0 = 22.7 – 3.3t

    3.3t = 22.7

    t = 22.7/3.3 = 6.9 s

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