An aircraft has a liftoff speed of 33 m/s. What minimum constant acceleration does this require if the aircraft is to be airborne after a ta

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An aircraft has a liftoff speed of 33 m/s. What minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 240 m

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  1. Answer:

    2.27 m/s²

    Explanation:

    Recall that one of the equations of motion can be expressed as

    v² = u² + 2as

    where

    v = final velocity = takeoff speed = 33m/s

    u = initial velocity = rest = 0 m/s

    a = acceleration ( we are asked to find this)

    s = distance traveled = length of takeoff run = 240m

    substituting the known values into the equation above,

    v² = u² + 2as

    33² = 0² + 2a(240)

    1089= 480a

    a = 1089/480

    a = 2.27 m/s²

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  2. ANSWER

    2.27 m/s^2

    EXPLANATION

    We can use the general relationship from kinematics:

    vf^2 = vi^2 + 2as

    where:

    s = distance;

    a = acceleration;

    vi = 0m/s is the initial velocity;

    vf=33ms is the final velocity.

    So:

    33^2 = 0^2 + 2 ⋅ a ⋅ 240

    a= 1089/480

    = 2.27m/s^2

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