Almost all medical schools require applicants to take the Medical College Admission Test (MCAT). To estimate the mean score of those who too

Question

Almost all medical schools require applicants to take the Medical College Admission Test (MCAT). To estimate the mean score of those who took the MCAT at WSSU, you will obtain the scores of an SRS of students. The scores follow a Normal distribution, and from published information you know that the standard deviation is 6.5. Suppose that (unknown to you) the mean score of those taking the MCAT at WSSU is 25.0. You sample 25 students. What is the standard deviation of the sampling distribution of x-bar?

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Thu Cúc 3 years 2021-08-24T02:02:03+00:00 1 Answers 8 views 0

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  1. ThanhThu
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    2021-08-24T02:03:31+00:00
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    Answer:

    1.3

    Step-by-step explanation:

    The given parameters are;

    The standard deviation, σ = 6.5

    The mean score, \overline X = 25.0

    The number of students in the sample, n = 25 students

    Whereby the standard deviation of the sampling distribution of \overline X is the standard deviation of \overline X, we have;

    The standard deviation of \overline X= σ/√(n)

    ∴ The standard deviation of \overline X= 6.5/√(25) = 1.3

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