Air enters a horizontal, well-insulated nozzle operating at steady state at 12 bar, 500 K, with a velocity of 50 m/s and exits at 7 bar, 440

Question

Air enters a horizontal, well-insulated nozzle operating at steady state at 12 bar, 500 K, with a velocity of 50 m/s and exits at 7 bar, 440 K. The mass flow rate is 1 kg/s. Determine the net force, in N, exerted by the air on the duct in the direction offlow.Answer:

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King 3 years 2021-09-02T02:15:32+00:00 1 Answers 32 views 0

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  1. linhdan
    -1
    2021-09-02T02:16:45+00:00
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    Answer:

    The net force is 300.8 N

    Explanation:

    ∆H = Cp(T1 – T2) = 1/2(V2^2 – V1^2)

    Cp is the heat capacity of air at constant pressure = 1005 J/kg

    T1 is initial temperature of air = 500 K

    T2 is the exit temperature of air = 440 K

    V1 is the initial velocity of air = 50 m/s

    V2 is the exit velocity of air

    1005(500 – 440) = 1/2(V2^2 – 50^2)

    60,300×2 = V2^2 – 2,500

    V2^2 = 120,600 + 2,500 = 123,100

    V2 = sqrt(123,100) = 350.8 m/s

    Net force (F) = mass flow rate × change in velocity = 1 kg/s × (350.8 – 50)m/s = 1 kg/s × 300.8 m/s = 300.8 kgm/s^2 = 300.8 N

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