after leaving the runway, a plane’s angle of ascent is 16 degree and its speed is 267 feet per second. How many minutes will it take for the

Question

after leaving the runway, a plane’s angle of ascent is 16 degree and its speed is 267 feet per second. How many minutes will it take for the airplane to climb to a height of 12,500 feet?

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MichaelMet 5 months 2021-08-29T20:32:28+00:00 1 Answers 0 views 0

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    2021-08-29T20:33:44+00:00

    Answer:

    The time taken for the airplane to climb to a height of 12,500 feet is 2.83 minutes.

    Explanation:

    Given that,

    Angle of the plane of ascent, \theta=16^{\circ}

    Initial speed of the plane, u = 267 ft/s

    We need to find the time taken for the airplane to climb to a height of 12,500 feet. First lets find the vertical speed of the plane.

    u_y=u\ \sin\theta\\\\u_y=267\times \ \sin(16)\\\\u_y=73.59\ ft/s

    Let t is the time taken for the airplane to climb to a height of 12,500 feet. The speed of an object is given by :

    u=\dfrac{d}{t}\\\\t=\dfrac{d}{u}\\\\t=\dfrac{12500\ ft}{73.59\ ft/s}\\\\t=169.86\ seconds\\\\t=2.83\ min

    So, the time taken for the airplane to climb to a height of 12,500 feet is 2.83 minutes. Hence, this is the required solution.

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