According to the reaction, below, how many grams of aluminum are needed to react fully with 100 grams of sulfur? 2AL + 3s – Al2S3

Question

According to the reaction, below, how many grams of aluminum are needed to react fully with 100 grams of sulfur? 2AL + 3s – Al2S3

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Kiệt Gia 5 months 2021-09-05T08:22:49+00:00 1 Answers 0 views 0

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    2021-09-05T08:24:32+00:00

    Answer: 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.

    Explanation:

    To calculate the moles :

    \text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

    \text{Moles of} S=\frac{100g}{32g/mol}=3.125moles

    The balanced chemical equation is:

    2Al+3S\rightarrow Al_2S_3  

    According to stoichiometry :

    3 moles of S require = 2 moles of Al

    Thus 3.125 moles of S will require=\frac{2}{3}\times 3.125=2.08moles  of Al  

    Mass of Al=moles\times {\text {Molar mass}}=2.08moles\times 27g/mol=56.2g

    Thus 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.

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