According to the reaction, below, how many grams of aluminum are needed to react fully with 100 grams of sulfur? 2AL + 3s – Al2S3

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Chemistry Kiệt Gia 3 years 2021-09-05T08:22:49+00:00 2021-09-05T08:22:49+00:00 1 Answers 2 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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Xavia · Answer 1 · 2021-09-05T08:24:32+00:00

Xavia

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2021-09-05T08:24:32+00:00 September 5, 2021 at 8:24 am

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Answer: 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} S=\frac{100g}{32g/mol}=3.125moles$

The balanced chemical equation is:

$2Al+3S\rightarrow Al_2S_3$

According to stoichiometry :

3 moles of $S$ require = 2 moles of $Al$

Thus 3.125 moles of $S$ will require= $\frac{2}{3}\times 3.125=2.08moles$ of $Al$

Mass of $Al=moles\times {\text {Molar mass}}=2.08moles\times 27g/mol=56.2g$

Thus 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.