Share
A wheel of radius 0.5 m rotates with a constant angular speed about an axis perpendicular to its center. A point on the wheel that is 0.2 m
Question
A wheel of radius 0.5 m rotates with a constant angular speed about an axis perpendicular to its center. A point on the wheel that is 0.2 m from the center has a tangential speed of 2 m/s. Determine the tangential acceleration of the point that is 0.2 m from the center.
in progress
0
Physics
3 years
2021-08-06T19:12:33+00:00
2021-08-06T19:12:33+00:00 1 Answers
131 views
0
Answers ( )
Answer:
The tangential acceleration is 0 m/s².
Explanation:
Given:
Radius of the wheel = 0.5 m
The point of observation for calculating tangential acceleration = 0.2 m from center.
Tangential speed at the point of observation = 2 m/s
The angular speed of the wheel is a constant.
In order to determine the tangential acceleration, we make use of the following formula:
Tangential acceleration at a point = Angular acceleration × Distance of the point from center
Or,![Rendered by QuickLaTeX.com a_t=\alpha \times r](https://documen.tv/wp-content/ql-cache/quicklatex.com-0e79b06c93103ad72eb472da0c38830d_l3.png)
Now, angular acceleration is defined as the rate of change of angular speed.
Here, the angular speed of the wheel is a constant. So, the change of angular speed is 0. Therefore, the angular acceleration is also 0 rad/s².
Now, from the above formula, as angular acceleration is 0, the magnitude of tangential acceleration at a point that is 0.2 m from the center of the wheel is also 0 m/s².