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## A wheel of radius 0.5 m rotates with a constant angular speed about an axis perpendicular to its center. A point on the wheel that is 0.2 m

Question

A wheel of radius 0.5 m rotates with a constant angular speed about an axis perpendicular to its center. A point on the wheel that is 0.2 m from the center has a tangential speed of 2 m/s. Determine the tangential acceleration of the point that is 0.2 m from the center.

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Physics
3 years
2021-08-06T19:12:33+00:00
2021-08-06T19:12:33+00:00 1 Answers
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## Answers ( )

Answer:The tangential acceleration is 0 m/s².Explanation:Given:

Radius of the wheel = 0.5 m

The point of observation for calculating tangential acceleration = 0.2 m from center.

Tangential speed at the point of observation = 2 m/s

The

angular speed of the wheel is a constant.In order to determine the tangential acceleration, we make use of the following formula:

Tangential acceleration at a point = Angular acceleration × Distance of the point from centerOr,

Now,

angular acceleration is defined as the rate of change of angular speed.Here, the angular speed of the wheel is a constant. So,

the change of angular speed is 0. Therefore, the angular acceleration is also 0 rad/s².Now, from the above formula,

as angular acceleration is 0, the magnitude of tangential acceleration at a point that is 0.2 m from the center of the wheel is also 0 m/s².