A water jet that leaves a nozzle at 78 m/s at a flow rate of 120 kg/s is to be used to generate power by striking the buckets located on the

Question

A water jet that leaves a nozzle at 78 m/s at a flow rate of 120 kg/s is to be used to generate power by striking the buckets located on the perimeter of a wheel. Determine the power generation potential of this water jet. Assume that the water jet flows steadily at the specified speed and flow rate. (Round the final answer to two decimal places.) The power generation potential is kW.

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Adela 3 years 2021-07-22T04:26:12+00:00 1 Answers 155 views 0

Answers ( )

  1. minhkhue
    0
    2021-07-22T04:27:24+00:00
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    Answer:

    The  value is E = 365040 J/s

    Explanation:

    From the question we are told that

       The  speed of the water jet is  v = 78 \ m/s

        The  flow rate of the water jet is  \r m = 120 \ kg /s

    Generally the mechanically energy possessed by a water flow is mathematically represented as

               E = \r m * e

    Here here e  is the specific mechanical energy generated which is mathematically represented as

              e[KJ/kg] = FE + KE + PE

    Here  

         FE – flow  energy

        KE  – kinetic energy

        PE  –  potential energy

    Generally give that we are only considering the power generation due to the kinetic energy of the water we have that

           E = \r m * KE

    Here  

         KE = \frac{v^2}{2}

        E = \r m * \frac{v^2}{2}

    =>    E = 120 * \frac{78^2}{2}

    =>    E = 365040 J/s

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