A volumetric flask made of Pyrex is calibrated at 20.0°C. It is filled to the 285-mL mark with 40.5°C glycerin. After the flask is filled, t

Question

A volumetric flask made of Pyrex is calibrated at 20.0°C. It is filled to the 285-mL mark with 40.5°C glycerin. After the flask is filled, the glycerin cools and the flask warms so that the combination of glycerin and flask reaches a uniform temperature of 32.0°C. The combination is then cooled back to 20.0°C
What is the volume of the glycerin when it cools to 20.0°C?

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Kim Chi 4 years 2021-07-20T22:39:47+00:00 1 Answers 2 views 0

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  1. sori
    0
    2021-07-20T22:40:53+00:00
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    Answer:

    V_f = 287.04 mL

    Explanation:

    We are given the initial/original volume of the glycerine as 285 mL.

    Now, after it is finally cooled back to 20.0 °C , its volume is given by the formula;

    V_f = V_i (1 + βΔT)

    Where;

    V_f is the final volume

    V_i is the original volume = 285 mL

    β is the coefficient of expansion of glycerine and from online tables, it has a value of 5.97 × 10^(-4) °C^(−1)

    Δt is change in temperature = final temperature – initial temperature = 32 – 20 = 12 °C

    Thus, plugging in relevant values;

    V_f = 285(1 + (5.97 × 10^(-4) × 12))

    V_f = 287.04 mL

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