A velocity selector in a mass spectrometer uses a 0.150 T magnetic field. (a) What electric field strength (in volts per meter) is needed to

Question

A velocity selector in a mass spectrometer uses a 0.150 T magnetic field. (a) What electric field strength (in volts per meter) is needed to select a speed of 4.40 ✕ 106 m/s? V/m

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Doris 2 weeks 2021-09-05T16:26:04+00:00 1 Answers 0 views 0

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    2021-09-05T16:27:58+00:00

    Answer:

    The electric field strength is 6.6\times10^{5}\ V/m

    Explanation:

    Given that,

    Magnetic field = 0.150 T

    Speed v= 4.40\times10^{6}\ m/s

    We need to calculate the electric field strength

    Using formula of velocity

    v=\dfrac{E}{B}

    E=v\times B

    Where, v = speed

    B = magnetic field

    Put the value into the formula

    E=4.40\times10^{6}\times0.150

    E=660000\ V/m

    E=6.6\times10^{5}\ V/m

    Hence, The electric field strength is 6.6\times10^{5}\ V/m

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