A uniformly charged ring of radius 10.0 cm has a total charge of 71.0 μC. Find the electric field on the axis of the ring at the following d

Question

A uniformly charged ring of radius 10.0 cm has a total charge of 71.0 μC. Find the electric field on the axis of the ring at the following distances from the center of the ring. (Choose the x-axis to point along the axis of the ring.)
(a) 1.00 cm
What is the general expression for the electric field along the axis of a uniformly charged ring? i MN/C
(b) 5.00 cm
i MN/C
(c) 30.0 cm
i MN/C
(d) 100 cm
i MN/C

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Euphemia 3 years 2021-08-31T18:53:41+00:00 1 Answers 8 views 0

Answers ( )

    0
    2021-08-31T18:55:19+00:00

    Answer:

    General Expression: E = kql/(l² + r²)^(3/2)

    (a) 6.3 MN/C

    (b) 22.8 MN/C

    (c) 6.1 MN/C

    (d) 0.63 MN/C

    Explanation:

    The general expression for electric field along axis of a uniformly charged ring is:

    E = kqL/(L² + r²)^(3/2)

    where,

    E = Electric Field Strength = ?

    k = Coulomb’s Constant = 9 x 10⁹ N.m²/C²

    q = Total Charge = 71 μC = 71 x 10⁻⁶ C

    L = Distance from center on axis

    r = radius of ring = 10 cm = 0.1 m

    (a)

    L = 1 cm = 0.01 m

    Therefore,

    E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.01 m)/[(0.01 m)² + (0.1 m)²]^(3/2)

    E = (6390 N.m³/C)/(0.00101 m³)

    E =  6.3 x 10⁶ N/C = 6.3 MN/C

    (b)

    L = 5 cm = 0.05 m

    Therefore,

    E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.05 m)/[(0.05 m)² + (0.1 m)²]^(3/2)

    E = (31950 N.m³/C)/(0.00139 m³)

    E =  22.8 x 10⁶ N/C = 27.4 MN/C

    (c)

    L = 30 cm = 0.3 m

    Therefore,

    E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.3 m)/[(0.3 m)² + (0.1 m)²]^(3/2)

    E = (191700 N.m³/C)/(0.03162 m³)

    E =  6.1 x 10⁶ N/C = 6.1 MN/C

    (d)

    L = 100 cm = 1 m

    Therefore,

    E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(1 m)/[(1 m)² + (0.1 m)²]^(3/2)

    E = (639000 N.m³/C)/(1.015 m³)

    E =  0.63 x 10⁶ N/C = 0.63 MN/C

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