A uniform string of length 10.0 m and weight 0.32 N is attached to the ceiling. A weight of 1.00 kN hangs from its lower end. The lower end

Question

A uniform string of length 10.0 m and weight 0.32 N is attached to the ceiling. A weight of 1.00 kN hangs from its lower end. The lower end of the string is suddenly displaced horizontally. How long does it take the resulting wave pulse to travel to the upper end

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Diễm Thu 3 years 2021-08-12T21:09:58+00:00 1 Answers 19 views 0

Answers ( )

  1. Sigrid
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    2021-08-12T21:11:50+00:00
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    Answer: 0.0180701 s

    Explanation:

    Given the following :

    Length of string (L) = 10 m

    Weight of string (W) = 0.32 N

    Weight attached to lower end = 1kN = 1×10^3

    Using the relation:

    Time (t) = √ (weight of string * Length) / weight attached to lower end * acceleration due to gravity

    g = acceleration due to gravity = 9.8m/s^2

    Weight of string = 0.32N

    Time(t) = √ (0.32 * 10) / [(1*10^3) * (9.8)]

    Time = √3.2 / 9800

    = √0.0003265

    = 0.0180701s

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