A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the mass of the

Question

A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the mass of the insect to be 7.0g , and assume the wings move an average downward distance of 1.5cm during each stroke. Assuming 117 downward strokes per second, estimate the average power output of the insect.

in progress 0
Doris 3 years 2021-09-03T18:11:08+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-09-03T18:12:46+00:00

    Answer:

    Average power = 0.240Watts

    Explanation:

    The insect requires double the force on its wings to counteract the gravitational force pulling it down.it generates upward force as below

    Upward Force=2Gravitational force

    force =2x(mass x gravitational pull)

    F=(0.007×9,8)x 2

    F=0.137 Nm

    Power generated is =work/time

    power =force *displacement/time

    convert 1.5cm to SI units meters=0.015meters

    displacement in one second is=0.015 x number of strokes

    displacement =0.015*117

    displacement =1.755 meters

    power=(0.137*1.755)/1second

    power=0.240 Watts

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )