A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the mass of the

Question

A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the mass of the insect to be 7.0g , and assume the wings move an average downward distance of 1.5cm during each stroke. Assuming 117 downward strokes per second, estimate the average power output of the insect.

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Gerda 3 years 2021-09-03T18:15:46+00:00 1 Answers 110 views 0

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    2021-09-03T18:16:46+00:00

    Answer:

    Average power output of insect is 2.42W

    Explanation:

    Workdone by constant force during displacement is given by:

    W= F× d cos theta

    Where theta is angle between F and d.

    Power output due to the force over the interval time is given by:

    P= Workdone/change in time

    Ginen:

    Mass of insect,m= 7.0g= 7/1000 = 0.07kg

    Downward force applied by insect,F= 2mg

    Distance moved by the wing each stroke=1.5cm=1.5/100= 0.015m

    W= F× d cos theta

    Where theta=0° since force is in the same direction as the displacement.

    W= 2mg×d

    W= 2× 0.07 × 9.8 × 0.015

    W= 0.02058J

    Power output = W/ change in time

    Since wings make 117strokes each second time interval is 1/117 = 8.5×10^-3seconds

    Power= 0.02058/(8.5×10^-3)

    Power= 2.42W

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