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A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the mass of the
Question
A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the mass of the insect to be 7.0g , and assume the wings move an average downward distance of 1.5cm during each stroke. Assuming 117 downward strokes per second, estimate the average power output of the insect.
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Physics
3 years
2021-09-03T18:15:46+00:00
2021-09-03T18:15:46+00:00 1 Answers
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Answer:
Average power output of insect is 2.42W
Explanation:
Workdone by constant force during displacement is given by:
W= F× d cos theta
Where theta is angle between F and d.
Power output due to the force over the interval time is given by:
P= Workdone/change in time
Ginen:
Mass of insect,m= 7.0g= 7/1000 = 0.07kg
Downward force applied by insect,F= 2mg
Distance moved by the wing each stroke=1.5cm=1.5/100= 0.015m
W= F× d cos theta
Where theta=0° since force is in the same direction as the displacement.
W= 2mg×d
W= 2× 0.07 × 9.8 × 0.015
W= 0.02058J
Power output = W/ change in time
Since wings make 117strokes each second time interval is 1/117 = 8.5×10^-3seconds
Power= 0.02058/(8.5×10^-3)
Power= 2.42W