A trap-jaw ant snaps its mandibles shut at very high speed, good for catching small prey. But these ants also slam their mandibles into the

Question

A trap-jaw ant snaps its mandibles shut at very high speed, good for catching small prey. But these ants also slam their mandibles into the ground; the resulting force can launch the ant into the air for a quick escape. If a 12 mg ant hits the ground with an average force of 47 mN for a time of 0.13 ms, at what speed will it leave the ground?

in progress 0
Nguyệt Ánh 5 months 2021-08-27T12:17:51+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-08-27T12:18:57+00:00

    Answer:

    FInal speed (v) = 0.509 m/s (Approx)

    Explanation:

    Given:

    Mass of ant (m) = 12 mg

    Force (f) = 47 N

    Time taken (t) = 0.13 ms

    Find:

    FInal speed (v) = ?

    Computation:

    Initial velocity (u) = 0

    Impulse = change in momentum

    Force × TIme = change in momentum

    47 × 0.13 = mv – mu

    6.11 = 12 (V)

    FInal speed (v) = 0.509 m/s (Approx)

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )