## A straight, stiff, horizontal wire of length 46 cm and mass 20 g is connected to a source of emf by light, flexible leads. A magnetic field

Question

A straight, stiff, horizontal wire of length 46 cm and mass 20 g is connected to a source of emf by light, flexible leads. A magnetic field of 1.33 T is horizontal and perpendicular to the wire. 1)Find the current necessary to float the wire, that is, find the current for which the magnetic force balances the weight of the wire.

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2021-07-22T01:37:10+00:00
2021-07-22T01:37:10+00:00 1 Answers
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## Answers ( )

Answer:0.32 A

Explanation:Weight of the wire = m × g where m, mass = (20 g / 1000 g) × 1 kg = 0.02 kg and g = 9.8 m/s²

Magnetic force = I L B sinα and α is 90°

and weight of the wire = magnetic force

0.02 kg × 9.8 m/s² = I × 0.46 m × 1.33 × 1

I, current = 0.02 kg × 9.8 m/s² / ( 0.46 m × 1.33T) = 0.32 A