A stone is thrown with an initial speed of 12 m/s at an angle of 30o above the horizontal from the top edge of a cliff. If it takes the ston

Question

A stone is thrown with an initial speed of 12 m/s at an angle of 30o above the horizontal from the top edge of a cliff. If it takes the stone 5.6 s to reach the bottom, how far does the stone travel horizontally

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Diễm Thu 3 years 2021-07-14T07:12:29+00:00 1 Answers 12 views 0

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    2021-07-14T07:13:47+00:00

    Answer:

    d=58m

    Explanation:

    From the question we are told that:

    Initial Speed U=12m/s

    Time T=5.6s

    Angle \theta=30

    Generally the  Newton’s equation for motion is mathematically given by

    d=d'+ut+\frac{at^2}{2}

    d=12cos30*5.6

    d=58m

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