a stone is thrown vertically upward with an initial velocity of 14m/sc negleting in air resistance find (a)Maximum height reached and (b)Tim

Question

a stone is thrown vertically upward with an initial velocity of 14m/sc negleting in air resistance find (a)Maximum height reached and (b)Time taken before it reached the ground ​

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Helga 4 years 2021-07-26T17:05:29+00:00 1 Answers 31 views 0

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  1. Neala
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    2021-07-26T17:06:41+00:00
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    Answer:

    1/2 m v^2 = m g H      conservation of energy

    H = (v^2 / (2 * g))^1/2 = (14^2 / 19.6)^1/2 = 10 m

    H = 1/2 g t^2       time to fall 10 m

    t = (2 * H / g)^1/2 = (20 / 9.8)^1/2 = 1.43 sec

    Total time in air = 2 * 1.43 = 2.86

    You can also use 2 a S = V0^2 since final velocity = 1.43 * 9.8 m/s = 14 m / s

    and 2 a S = 2 * 9.8 * 10 = 196 m^2 / s^2   which is V0 squared

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