A stone is thrown vertically upward with a speed of 24.0 ms. (a) How fast is it moving when it reaches a height of 13.0 m? (b) How much time

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A stone is thrown vertically upward with a speed of 24.0 ms. (a) How fast is it moving when it reaches a height of 13.0 m? (b) How much time is required to reach this height?

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Gerda 3 years 2021-07-16T17:42:41+00:00 1 Answers 9 views 0

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  1. Dulcie
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    2021-07-16T17:44:12+00:00
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    Answer:

    Question A:17.92 m/s

    Question B:0.6 seconds

    Explanation:

    Question A:

    Initial velocity(u)=24m/s

    Height(h)=13m

    acceleration due to gravity(g)=9.8m/s^2

    Final velocity=v

    v^2=u^2-2xgxh

    v^2=24^2-2×9.8×13

    v^2=24×24-2×9.8×13

    v^2=576-254.8

    v^2=321.2

    Take them square root of both sides

    v=√(321.2)

    v=17.92m/s

    Question B:

    velocity(v)=17.92m/s

    Acceleration due to gravity(g)=9.8m/s^2

    Initial velocity(u)=24m/s

    Time=t

    v=u-gxt

    17.92=24-9.8xt

    Collect like terms

    9.8t=24-17.92

    9.8t=6.08

    Divide both sides by 9.8

    9.8t/9.8=6.08/9.8

    t=0.6 approximately

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